Will somebody calculate some things and see if that fish will make it into the other bowl this is serious
This is going to be a fairly simple ballistics/parabola problem- We just need to see if the fish lands anywhere in the range of the opening of the second bowl. Pixels are an accurate measure of the actual image, so we need to figure out some sort of pixel to centimeter conversion. Fish bowls can vary in size, but the fish bowl I have has a rim of 12.7 centimeters. The computer puts the rim at 120 pixels wide, which means that 120 pixels=12.7 centimeters, or that 9px=1cm.
We’re gonna measure the horizontal distance the fish needs to travel, because that’s what really matters. and it means that we don’t have to factor in any change of height. So, measuring from where the water trail meets the rim of the first bowl, to either side of the rim of the second bowl, the fish needs to travel between 150 and 270 pixels, or 16.7 and 30 centimeters.
Now we get to the tricky part- we need to know the velocity of the fish. Ordinarily we would be at a loss without the relevant data, but how could we let you down like that? The only clue we have is the trail of water droplets trailing behind the fish, but even that indicates a fairly significant velocity. (reminder- velocity is distance over time, in this case meters per second)
So, in the name of science, I am going to get a fish-like object and haul it out of some water, and estimate a velocity based on that.
My fish-like object (with a plastic tail!)
My experimental setup! (the ruler is in inches cuz it’s an art ruler- my unit converter app got a lot of use while I was doing this)
A meter is too long, so we’re gonna pull the ‘fish’ a half meter out of the water the until we get something close, and time how long it takes to go that distance. I’d give you pictures but I only have two hands.
Basically, I needed to get a trail a bit over 10 cm high, with the fish starting from about 5 cm below the surface. And, amazingly enough, I got a trail of about the right size at .55 seconds, which means that it was moving at just under a meter per second, so we’re gonna call the velocity 1 m/s
Now all we need is the angle at which the fish is exiting the bowl, which we can just use pixels and sines/cosines/whatever for. Aaaaand, wow, the distance from where the water trail exits the bowl to where it ends is exactly 37 by 37 pixels, which means that the fish is leaving at exactly a 45 degree angle! Either something magical is happening here, or the stock photographers really wanted to make things easy for me ;)
Now we can plug our numbers into the formula, which is really simple thanks to the 45 degree angle and the lack of height change.
Here’s the formula as sourced by wikipedia:
Gravity is 9.8m/s², assuming this fish is jumping on Earth, and velocity is 1 m/s. Velocity squared is 1m²/s², so we know the units will cancel out, leaving us with distance in meters. So, with one divided by 9.8, we get 0.10 meters, which is almost exactly 10 centimeters.
Remember earlier where we calculated that the fish would have to travel at least 16.7 cm to make it into the other bowl? Yeah, I’m very sorry, but the fish wouldn’t make it- at best it would just hit the bowl and slide off. Technically I think that 10cm would be the location of the tail of the fish, but 7cm is enough distance that it still wouldn’t make it in, though there was definitely enough guesswork in this calculation (especially in how I got the velocity) that it might be possible for the fish to make it that far, but probably not.
TL;DR, Nope (probably), but I did science and math to find out!